

A127629


Numbers n such that a divisor, together with its quotient and remainder, are consecutive terms (in that order) in a geometric sequence.


0



9, 28, 34, 58, 65, 75, 110, 126, 132, 201, 205, 217, 224, 246, 254, 258, 294, 344, 384, 399, 436, 498, 502, 513, 516, 520, 579, 657, 680, 690, 730, 786, 810, 866, 880, 978, 979, 1001, 1008, 1028, 1038, 1105, 1128, 1164, 1330, 1332, 1365, 1370, 1374, 1388
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OFFSET

1,1


COMMENTS

The sequence misses the primes.


LINKS

Table of n, a(n) for n=1..50.
C. Hughes, Geometric Division


EXAMPLE

58 is in the sequence because 58 = 9*6 + 4, where 9, 6 and 4 are consecutive terms in a geometric sequence.


PROG

(PARI) a(n)={for(d=1, n, if((n\d)*(n%d)==d^2, return(1))); return(0)}


CROSSREFS

Sequence in context: A031454 A044999 A155473 * A267686 A024670 A141805
Adjacent sequences: A127626 A127627 A127628 * A127630 A127631 A127632


KEYWORD

easy,nonn


AUTHOR

Nick Hobson (nickh(AT)qbyte.org), Jan 20 2007


STATUS

approved



