%I #10 Dec 21 2022 08:19:59
%S 0,0,0,1,0,0,0,1,0,0,1,0,2,1,0,0,0,1,0,0,1,0,2,1,0,0,1,0,2,1,0,3,2,1,
%T 0,0,0,1,0,0,1,0,2,1,0,0,1,0,2,1,0,3,2,1,0,0,1,0,2,1,0,3,2,1,0,4,3,2,
%U 1,0,0,0,1,0,0,1,0,2,1,0,0,1,0,2,1,0,3,2,1,0,0,1,0,2,1,0,3,2,1,0,4,3,2,1,0
%N Hypertetrahedron with T(W,X,Y,Z) = Y - Z.
%C Together with A127324, A127326 and A127327 might enable reading "by antidiagonals" of hypercube arrays as 4-dimensional analog of A056558, A056560 and A056559 with cubical arrays.
%F a(n) = A127323(n) - A127324(n).
%e a(23)=1 because A127323(23) - A127324(23) = 1.
%e See A127327 for a table of A127324, A127325, A127326, A127327.
%Y Cf. A127321, A127322, A127323, A127324, A127326, A127327.
%Y Cf. A056558, A056560, A056559.
%K nonn
%O 0,13
%A _Graeme McRae_, Jan 10 2007