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A127268
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If the prime factorization of n is n = Product_{p|n} p^b(p,n) (p = distinct prime divisors of n, each b(p,n) is a positive integer), then a(n) is (Sum_{p|n} p^b(p,n)) taken mod (Sum_{p|n} p).
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1
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0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 0, 0, 1, 0, 2, 0, 0, 0, 1, 0, 0, 0, 2, 0, 0, 0, 0, 0, 0, 0, 3, 0, 0, 0, 6, 0, 0, 0, 2, 6, 0, 0, 4, 0, 6, 0, 2, 0, 4, 0, 6, 0, 0, 0, 2, 0, 0, 6, 0, 0, 0, 0, 2, 0, 0, 0, 2, 0, 0, 4, 2, 0, 0, 0, 0, 0, 0, 0, 2, 0, 0, 0, 6, 0, 6, 0, 2, 0, 0, 0, 0, 0, 6, 6, 1
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OFFSET
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1,12
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LINKS
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FORMULA
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EXAMPLE
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40 = 2^3 *5^1. So a(40) = 2^3 + 5^1 (mod (2+5)) = 13 (mod 7) = 6.
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MAPLE
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A008475 := proc(n) local ifs ; if n =1 then 0; else ifs := ifactors(n)[2] ; add(op(1, i)^op(2, i), i =ifs) ; fi ; end: A008472 := proc(n) local ifs ; if n =1 then 0; else ifs := ifactors(n)[2] ; add(op(1, i), i =ifs) ; fi ; end: A127268 := proc(n) if n = 1 then 0 ; else A008475(n) mod A008472(n) ; fi ; end: seq(A127268(n), n=1..100) ; # R. J. Mathar, Nov 01 2007
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MATHEMATICA
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Array[Mod[Total@ Apply[Power, # /. {1, 1} -> {0, 1}, 1], Total[#[[All, 1]] ]] &@ FactorInteger[#] &, 100] (* Michael De Vlieger, Nov 20 2017 *)
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PROG
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(PARI)
A008475(n) = { my(f=factor(n)); vecsum(vector(#f~, i, f[i, 1]^f[i, 2])); };
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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