

A126933


Take the decimal number formed by the first n digits of A023396 in reverse order and divide by 2^n.


2



1, 3, 14, 132, 691, 1908, 16579, 47352, 414301, 1183713, 5474669, 27151397, 135646011, 678174568, 6442602909, 18480090517, 85533990571
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OFFSET

1,2


COMMENTS

The sequence A023396 gives ndigit numbers consisting entirely of 1s and 2s which are divisible by 2^n. The quotients upon division form the present sequence. The parity of the nth term here determines the next term in A023396; if even, it is a 1 and if odd, a 2.
This was set as a problem in the All Union Mathematical Olympiad of 1971 and can be found in the reference cited here.


REFERENCES

J. B. Tabov and P. J. Taylor, Methods of Problem Solving, Book 1, Australian Mathematics Trust, 1996.


LINKS

Table of n, a(n) for n=1..17.


CROSSREFS

Sequence in context: A186772 A061029 A096657 * A073550 A002966 A075654
Adjacent sequences: A126930 A126931 A126932 * A126934 A126935 A126936


KEYWORD

nonn,base


AUTHOR

Gerry Leversha (g.leversha(AT)btinternet.com), Mar 18 2007


STATUS

approved



