

A126257


Number of distinct new terms in row n of Pascal's triangle.


8



1, 0, 1, 1, 2, 2, 2, 3, 4, 4, 4, 5, 6, 6, 7, 5, 7, 8, 9, 9, 9, 8, 11, 11, 12, 12, 13, 13, 13, 14, 15, 15, 16, 16, 17, 16, 17, 18, 19, 19, 20, 20, 21, 21, 22, 21, 23, 23, 24, 24, 25, 25, 26, 26, 27, 26, 26, 28, 29, 29, 30, 30, 31, 31, 32, 32, 32, 33, 34, 34, 34, 35, 36, 36, 37, 37, 38
(list;
graph;
refs;
listen;
history;
text;
internal format)



OFFSET

0,5


COMMENTS

Partial sums are in A126256.
n occurs a(n) times in A265912.  Reinhard Zumkeller, Dec 18 2015


LINKS

N. Hobson, Table of n, a(n) for n = 0..1000
N. Hobson, Home page (listed in lieu of email address)
Nick Hobson, Python program for this sequence


EXAMPLE

Row 6 of Pascal's triangle is: 1, 6, 15, 20, 15, 6, 1. Of these terms, only 15 and 20 do not appear in rows 05. Hence a(6)=2.


PROG

(PARI) lim=77; z=listcreate(1+lim^2\4); print1(1, ", "); r=1; for(a=1, lim, for(b=1, a\2, s=Str(binomial(a, b)); f=setsearch(z, s, 1); if(f, listinsert(z, s, f))); print1(1+#zr, ", "); r=1+#z)
(Haskell)
import Data.List.Ordered (minus, union)
a126257 n = a126257_list !! n
a126257_list = f [] a034868_tabf where
f zs (xs:xss) = (length ys) : f (ys `union` zs) xss
where ys = xs `minus` zs
 Reinhard Zumkeller, Dec 18 2015


CROSSREFS

Cf. A007318, A062854, A126254A126256.
Cf. A034868, A265912.
Sequence in context: A194165 A004524 A265409 * A025773 A285763 A294621
Adjacent sequences: A126254 A126255 A126256 * A126258 A126259 A126260


KEYWORD

easy,nonn


AUTHOR

Nick Hobson Dec 24 2006


STATUS

approved



