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A125301
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a(3n) = n, a(3n+1) = (n+2)*a(3n), a(3n+2) = (n+2)*a(3n+1).
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1
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0, 0, 0, 1, 3, 9, 2, 8, 32, 3, 15, 75, 4, 24, 144, 5, 35, 245, 6, 48, 384, 7, 63, 567, 8, 80, 800, 9, 99, 1089, 10, 120, 1440, 11, 143, 1859, 12, 168, 2352, 13, 195, 2925, 14, 224, 3584, 15, 255, 4335, 16, 288, 5184, 17, 323, 6137, 18, 360, 7200, 19, 399, 8379, 20
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OFFSET
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0,5
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COMMENTS
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From a competency test.
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LINKS
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Index entries for linear recurrences with constant coefficients, signature (0,0,4,0,0,-6,0,0,4,0,0,-1).
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FORMULA
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a(n) = 4*a(n-3) - 6*a(n-6) + 4*a(n-9) - a(n-12) for n>11.
G.f.: x^3*(1 + 3*x + 9*x^2 - 2*x^3 - 4*x^4 - 4*x^5 + x^6 + x^7 + x^8) / ((1 - x)^4*(1 + x + x^2)^4).
(End)
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MAPLE
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a:=proc(n): if n mod 3=0 then n/3 elif n mod 3 = 1 then (n+5)*a(n-1)/3 else (n+4)*a(n-1)/3 fi end: seq(a(n), n=0..75); # Emeric Deutsch, Jan 01 2007
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MATHEMATICA
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LinearRecurrence[{0, 0, 4, 0, 0, -6, 0, 0, 4, 0, 0, -1}, {0, 0, 0, 1, 3, 9, 2, 8, 32, 3, 15, 75}, 70] (* Harvey P. Dale, Jul 31 2018 *)
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PROG
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(PARI) concat(vector(3), Vec(x^3*(1 + 3*x + 9*x^2 - 2*x^3 - 4*x^4 - 4*x^5 + x^6 + x^7 + x^8) / ((1 - x)^4*(1 + x + x^2)^4) + O(x^100))) \\ Colin Barker, Jan 24 2017
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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Trent Stratton (trent.stratton(AT)gov.bc.ca), Dec 08 2006
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EXTENSIONS
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STATUS
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approved
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