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Sum[ i^j^k, {i,1,n}, {j,1,n}, {k,1,n} ].
2

%I #5 May 15 2013 18:01:20

%S 1,28,7625731729896,

%T 13407807929942597099574024998205985135931742965325158317510351105024878248924471298029103219186757034747676158536830429928105045387310278568778808509188348

%N Sum[ i^j^k, {i,1,n}, {j,1,n}, {k,1,n} ].

%C The next term is too large to include.

%C Prime p divides a(p) for p = {2, 3, 7, 11, 23, 31, 43, 47, 59, 67, 71, 79, ...} = A039787[n] Primes p such that p-1 is squarefree. p^2 divides a(p) for prime p = {2,3}.

%F a(n) = Sum[ i^j^k, {i,1,n}, {j,1,n}, {k,1,n} ].

%t Table[Sum[i^j^k,{i,1,n},{j,1,n},{k,1,n}],{n,1,5}]

%o (PARI) a(n)=sum(i=1,n,sum(j=1,n,sum(k=1,n,i^j^k))) \\ _Charles R Greathouse IV_, May 15 2013

%Y Cf. A039787. Cf. A086787 - Sum[ i^j, {i, 1, n}, {j, 1, n} ].

%Y Numbers n that divide a(n) are listed in A124391(n) = {1, 2, 3, 4, 6, 7, 8, 9, 11, 12, 14, 16, 18, 20, 21, 22, 23, 24, 27, 28, 31, ...}.

%K nonn

%O 1,2

%A _Alexander Adamchuk_, Oct 09 2006