OFFSET
2,2
COMMENTS
No simple formula known, just a complicated sum over partitions.
Empirically a(n+1) = sum( d divides n, A000081(d) ), this holds for the terms given. If true, this sequences starts 1, 2, 3, 6, 10, 24, 49, 121, 289, 730, 1843, 4794, 12487, 33023, 87823, 235502, 634848, 1721469, 4688677, 12826962, 35221883, 97057025, 268282856, 743729893, 2067174655, ... . - Joerg Arndt, Sep 03 2015
EXAMPLE
a(5)=6 from the module 2 s[1, 1, 1, 1, 1] + 9 s[2, 1, 1, 1] + 14 s[2, 2, 1] + 14 s[3, 1, 1] + 14 s[3,2] + 13 s[4, 1] + 6 s[5].
CROSSREFS
KEYWORD
nonn,more
AUTHOR
F. Chapoton, Oct 09 2006
STATUS
approved