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A123132
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Describe prime factorization of n (primes in ascending order and with repetition) (method A - initial term is 2).
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3
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12, 13, 22, 15, 1213, 17, 32, 23, 1215, 111, 2213, 113, 1217, 1315, 42, 117, 1223, 119, 2215, 1317, 12111, 123, 3213, 25, 12113, 33, 2217, 129, 121315, 131, 52, 13111, 12117, 1517, 2223, 137, 12119, 13113, 3215, 141, 121317, 143, 22111, 2315, 12123
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OFFSET
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2,1
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COMMENTS
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Method A = 'frequency' followed by 'digit'-indication. Say 'what you see' in prime factors of n, n>1.
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LINKS
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EXAMPLE
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2 has "one 2" in its prime decomposition, so a(2)=12.
3 has "one 3" in its prime decomposition, so a(3)=13.
4=2*2 has "two 2" in its prime decomposition, so a(4)=22.
5 has "one 5" in its prime decomposition, so a(5)=15.
6=2*3 has "one 2 and one 3" in its prime decomposition, so a(6)=1213.
.....
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MATHEMATICA
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a[n_] := FromDigits@ Flatten@ IntegerDigits[ Reverse /@ FactorInteger@ n]; a/@ Range[2, 30] (* Giovanni Resta, Jun 16 2013 *)
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PROG
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(PARI) for(n=2, 25, factn=factor(n); for(i=1, omega(n), print1(factn[i, 2], factn[i, 1])); print1(", "))
(PARI) a(n) = my(factn=factor(n), sout = ""); for(i=1, omega(n), sout = concat(sout, Str(factn[i, 2])); sout = concat(sout, Str(factn[i, 1]))); eval(sout); \\ Michel Marcus, Jun 29 2017
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CROSSREFS
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KEYWORD
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nonn,base
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AUTHOR
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Herman Jamke (hermanjamke(AT)fastmail.fm), Sep 30 2006
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STATUS
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approved
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