|
| |
|
|
A122987
|
|
Possible last three digits of n^3 (leading zeros omitted).
|
|
3
| |
|
|
0, 1, 3, 7, 8, 9, 11, 13, 16, 17, 19, 21, 23, 24, 27, 29, 31, 32, 33, 37, 39, 41, 43, 47, 48, 49, 51, 53, 56, 57, 59, 61, 63, 64, 67, 69, 71, 72, 73, 77, 79, 81, 83, 87, 88, 89, 91, 93, 96, 97, 99, 101, 103, 104, 107, 109, 111, 112, 113, 117, 119
(list; graph; refs; listen; history; internal format)
|
|
|
|
OFFSET
| 1,3
|
|
|
COMMENTS
| This is a finite sequence. a(505) = 999 is the last term.
|
|
|
LINKS
| Nathaniel Johnston, Table of n, a(n) for n = 1..505 (full sequence)
Eric Weisstein's World of Mathematics, Cubic Numbers.
|
|
|
EXAMPLE
| The last three digits of n^3 can be 111, 112, 113, etc... but not 114, 115, 116, etc...
|
|
|
MAPLE
| s:={}: for n from 0 to 999 do s:=s union {n^3 mod 1000}: od: op(s); # Nathaniel Johnston, Jun 22 2011
|
|
|
CROSSREFS
| Cf. A000578, A122986, A122988.
Sequence in context: A059101 A091679 A116034 * A047530 A096315 A112680
Adjacent sequences: A122984 A122985 A122986 * A122988 A122989 A122990
|
|
|
KEYWORD
| base,fini,easy,nonn
|
|
|
AUTHOR
| Sergio Pimentel (ferdiego(AT)cox.net), Sep 22 2006
|
| |
|
|
