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The terms 70 and 90 show that sequence is strictly different from A042965. - Andrew Plewe, Jun 13 2007
Table of n, a(n) for n=1..72.
Numbers n such that A000224(n) <= A000010(n). Union of A122903 and A122904. Complement of A122905 in positive integers.
Cf. A122903, A122904, A122905, A122907.
Sequence in context: A179779 A183147 A074227 * A042965 A260003 A005848
Adjacent sequences: A122903 A122904 A122905 * A122907 A122908 A122909
Max Alekseyev, Sep 18 2006