1,2

The terms 70 and 90 show that sequence is strictly different from A042965. - Andrew Plewe, Jun 13 2007

Table of n, a(n) for n=1..72.

Numbers n such that A000224(n) <= A000010(n). Union of A122903 and A122904. Complement of A122905 in positive integers.

Cf. A122903, A122904, A122905, A122907.

Sequence in context: A179779 A183147 A074227 * A042965 A260003 A005848

Adjacent sequences: A122903 A122904 A122905 * A122907 A122908 A122909

nonn

Max Alekseyev, Sep 18 2006

approved