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%I #2 Mar 30 2012 18:59:15
%S 1,9,729,4782969,282429536481,150094635296999121,
%T 6461081889226673298932241,2503155504993241601315571986085849,
%U 8727963568087712425891397479476727340041449
%N Numerators of Hankel transform of 1/(3n+1) (conjecture).
%C General conjecture: numerators of Hankel transform of 1/(p*n+1) are given by (p^2)^sum{k=1..n, sum{j=0..n, floor(k/p^j)}}, for prime p.
%F a(n)=9^A122250(n); a(n)=9^sum{k=1..n, sum{j=0..n, floor(k/3^j)}};
%Y Cf. A122249.
%K easy,nonn
%O 0,2
%A _Paul Barry_, Aug 27 2006
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