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Numbers of the form (1+2n^2+3n^3)/(2n-1).
0

%I #4 Mar 30 2012 17:26:22

%S -1,0,3,6,11,20,62,111

%N Numbers of the form (1+2n^2+3n^3)/(2n-1).

%C Corresponding n's are 0, -1, -2, 1, 2, 3, -7, 8.

%K fini,full,sign

%O 1,3

%A _Zak Seidov_, Oct 17 2006