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A122060
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Position in decimal expansion of 1/n where repetition begins.
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0
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2, 3, 2, 4, 3, 3, 7, 5, 2, 3, 3, 4, 7, 8, 3, 6, 17, 3, 19, 4, 7, 4, 23, 5, 4, 8, 4, 11, 29, 3
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,1
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COMMENTS
| If 1/n = 0.XYYYYY... then sequence gives index of first digit of the second Y.
a(4) = 4 and a(p) = p for primes p = {7, 17, 19, 23, 29, 47, 59, 61, 97, ...} = A001913(n) Cyclic numbers: primes with primitive root 10. - Alexander Adamchuk (alex(AT)kolmogorov.com), Jan 28 2007
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FORMULA
| a(n)=A121341(n)+2 if 1/n terminates, else a(n)=A121341(n)+1. - R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Sep 20 2006
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EXAMPLE
| a(4) = 4 because in .2500 the zero begins repeating at the fourth position
a(17) = 17 because .52631578947368421053 begins repeating at the 17th position
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CROSSREFS
| Cf. A001913, A002371.
Sequence in context: A070296 A072645 A135817 * A088939 A004596 A118653
Adjacent sequences: A122057 A122058 A122059 * A122061 A122062 A122063
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KEYWORD
| nonn,base
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AUTHOR
| Ben Thurston (benthurston27(AT)yahoo.com), Sep 14 2006
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