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A121870
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Monthly Problem 10791, second expression.
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2
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1, 1, 2, 9, 61, 554, 6565, 96677, 1716730, 36072181, 881242577, 24674241834, 783024550969, 27896201305769, 1106485798248706, 48517267642373105, 2337333266369553253, 123040664089658462650, 7043260281573138384701, 436533086101058798529933
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OFFSET
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0,3
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LINKS
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FORMULA
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sqrt(a(n)) = upper left term in M^n as to the modulus of a polar term; M = an infinite square production matrix in which a column of (i, i, i, ...) is appended to the right of Pascal's triangle, as follows (with i = sqrt(-1)):
1, i, 0, 0, 0, ...
1, 1, i, 0, 0, ...
1, 2, 1, i, 0, ...
1, 3, 3, 1, i, ...
... (End)
a(n) = |B_n(i)|^2, where B_n(x) is the n-th Bell polynomial, i = sqrt(-1) is the imaginary unit. - Vladimir Reshetnikov, Oct 15 2017
a(n) ~ (n*exp(-1 + Re(LambertW(i*n)) / Abs(LambertW(i*n))^2) / Abs(LambertW(i*n)))^(2*n) / Abs(1 + LambertW(i*n)), where i is the imaginary unit. - Vaclav Kotesovec, Jul 28 2021
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MAPLE
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A121870a:= proc(a) local i, t:
i:=1: t:=0: for i to 100 do t:=t+evalf((i^(a-1))*(I)^i/(i)!): od:
RETURN(round(abs(t^2))):
end: a:= A121870a(n);
# Alternate:
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MATHEMATICA
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PROG
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(PARI) a(n) = abs( (sum(k=0, n, I^k*stirling(n, k, 2)))^2 );
(Magma) C<I>:= ComplexField(); a:= func< n | Round(Abs( (&+[I^k*StirlingSecond(n, k): k in [0..n]])^2 )) >;
(Sage) [abs( sum(I^k*stirling_number2(n, k) for k in (0..n))^2 ) for n in (0..25)] # G. C. Greubel, Oct 08 2019
(GAP) List([0..25], n-> (Sum([0..Int(n/2)], k-> Stirling2(n, 2*k)*(-1)^(k)) )^2 + (Sum([0..Int(n/2)], k-> (-1)^k*Stirling2(n, 2*k+1)))^2 ); # G. C. Greubel, Oct 08 2019
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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