|
%I #2 Mar 30 2012 17:26:21
%S 1,2,3,3,3,4,4,4,5,5,5,6,6,6,7,7,7,7,8,8,8,8,9,9,9,9,9,10,10,10,10,11,
%T 11,11,11,11,12,12,12,12,12,13,13,13,13,13,14,14,14,14,14,14,15,15,15,
%U 15,15,15,16,16,16,16,16,16,17,17,17,17,17,17,18,18,18,18,18,18,19,19
%N Smallest m such that m^3>=n^2.
%C If n is a cube a(n)=A100196(n), otherwise a(n)=A100196(n)+1. Also, a(n)=(A070923(n)+n^2)^(1/3).
%F a(n)=ceiling(n^(2/3)), n=1,2,...
%t Table[Ceiling[n^(2/3)],{n,1,100}]
%Y Cf. A070923, A100196.
%K nonn
%O 1,2
%A _Zak Seidov_, Aug 05 2006
|
