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a(n) = 2^(n*(3n+5)/2) = 2^A115067(n+1).
0

%I #10 Oct 18 2024 01:41:51

%S 1,16,2048,2097152,17179869184,1125899906842624,590295810358705651712,

%T 2475880078570760549798248448,83076749736557242056487941267521536,

%U 22300745198530623141535718272648361505980416

%N a(n) = 2^(n*(3n+5)/2) = 2^A115067(n+1).

%C Apparently this sequence is the Hankel transform of A098329 = [1, 1, 17, 49, 481, 2081, ...]; example : Det([1]) = 1, Det([1,1 ; 1,17]) = 16, Det([1,1,17 ; 1,17,49 ; 17,49,481]) = 2048, ...

%t Table[2^(n(3n+5)/2),{n,0,9}] (* _James C. McMahon_, Oct 17 2024 *)

%Y Cf. A098329, A115067.

%K nonn

%O 0,2

%A _Philippe Deléham_, Sep 06 2006