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A121258
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a(n) = a(n-1)*a(n-2)*a(n-3) - 1 with a(0)=a(1)=a(2)=2.
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3
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OFFSET
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0,1
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COMMENTS
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Analog of A055937 a(n) = a(n-1)*a(n-2) - 1. What is the equivalent continued fraction and asymptotic representation, by analogy to A007660 a(n) = a(n-1)*a(n-2) + 1?
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LINKS
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FORMULA
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MATHEMATICA
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RecurrenceTable[{a[0]==a[1]==a[2]==2, a[n] == a[n-1]*a[n-2]*a[n-3] - 1}, a, {n, 0, 15}] (* G. C. Greubel, Jun 07 2019 *)
nxt[{a_, b_, c_}]:={b, c, a*b*c-1}; NestList[nxt, {2, 2, 2}, 10][[All, 1]] (* Harvey P. Dale, Jun 25 2020 *)
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PROG
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(Magma) I:=[2, 2, 2]; [n le 3 select I[n] else Self(n-1)*Self(n-2)* Self(n-3)-1: n in [1..12]]; // Vincenzo Librandi, Nov 14 2011
(PARI) a(n) = if(n<3, 2, a(n-1)*a(n-2)*a(n-3) - 1);
(Sage)
def a(n):
if (n==0 or n==1 or n==2): return 2
else: return a(n-1)*a(n-2)*a(n-3) - 1
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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