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 A121164 Triangle, real terms extracted from squares of paired terms in arithmetic sequences. 0
 -3, -8, -5, -15, -16, -7, -24, -33, -24, -9, -35, -56, -51, -32, -11, -48, -85, -88, -69, -40, -13, -63, -120, -135, -120, -87, -48, -15, -80, -161, -192, -185, -152, -105, -56, -17, -99, -208, -259, -264, -235, -184, -123, -19, -120, -261, -336, -357, -336, -285, -216, -141 (list; table; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS Left border (-3, -8, -15, -24...) unsigned = A013648. Next column (-5, -16, -33...) unsigned = A045944 LINKS FORMULA Form an array of the arithmetic sequences: (1, 2, 3...); (1, 3, 5...); (1, 4, 7...); and consider each pair as a complex term; e.g. (1 + 2i), (2 + 3i), then square each complex term and extract the real integer. Antidiagonals become rows of the triangle. EXAMPLE Array of the extracted real terms: -3, -5, -7, -9,... -8, -16, -24, -32,... -15,-33, -51, -69,... -24, -56,-88, -120,... ... Taking antidiagonals we get the triangle: -3; -8, -5; -15, -16, -7; -24, -33, -24, -9; -35, -56, -51, -32, -11; -48, -85, -88, -69, -40, -13; ... (3,2) = -16 since (taken from the arithmetic sequence 1, 3, 5...), (3 + 5i)^2 = (-16 + 30i). CROSSREFS Cf. A013648, A045944. Sequence in context: A166492 A120070 A143753 * A086872 A323760 A054792 Adjacent sequences:  A121161 A121162 A121163 * A121165 A121166 A121167 KEYWORD sign,tabl AUTHOR Gary W. Adamson, Aug 13 2006 STATUS approved

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Last modified March 18 17:51 EDT 2019. Contains 321292 sequences. (Running on oeis4.)