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a(n) = 3^(n^2) - 2^(n^2).
1

%I #21 Sep 08 2022 08:45:26

%S 0,1,65,19171,42981185,847255055011,150094566577522385,

%T 239299328667667576168771,3433683820274065740584139537665,

%U 443426488243035352096610401360800480451,515377520732011329768810529537391871205404316625

%N a(n) = 3^(n^2) - 2^(n^2).

%H Vincenzo Librandi, <a href="/A120801/b120801.txt">Table of n, a(n) for n = 0..40</a>

%t Table[3^(n^2) - 2^(n^2), {n, 0, 10}] (* _Harvey P. Dale_, Apr 06 2011 *)

%o (Magma) [3^(n^2) - 2^(n^2): n in [0..13]]; // _Vincenzo Librandi_, Feb 27 2013

%Y Cf. A007689, A001047.

%K nonn,easy

%O 0,3

%A _Mohammad K. Azarian_, Aug 18 2006

%E a(10) from _Harvey P. Dale_, Apr 06 2011