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A120392 a(1)=least k such that p(1)=(k*3)^2 + k*3 -1 is prime (so a(1)=1 as 3^2+3-1= 11 = p(1) = prime), then a(n+1)=least k such that (k*p(n))^2 + k*p(n) -1 = p(n+1) = prime. 0
1, 1, 1, 1, 13, 1, 101, 130, 109, 418 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,5

COMMENTS

p sequence starts 11,131,17291,298995971,15108361827832297751

LINKS

Table of n, a(n) for n=1..10.

CROSSREFS

Sequence in context: A040181 A123187 A046733 * A133371 A223515 A010223

Adjacent sequences:  A120389 A120390 A120391 * A120393 A120394 A120395

KEYWORD

nonn

AUTHOR

Pierre CAMI, Jul 01 2006

STATUS

approved

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Last modified November 27 02:34 EST 2014. Contains 250152 sequences.