|
%I #5 Jan 02 2024 14:12:55
%S 1,9,257875,940908897061,26038773205374138944970092886340352227,
%T 5706439637514064062030256049808675747470805004854626598761,
%U 3819751175863358416058062379293843331497647520922258560223903226691067255782388923965399403291707829
%N Numerator of Sum[ 1/k^p, {k,1,p-1} ], where p = Prime[n].
%C p^3 divides a(n) for n>2. A119722[n] = a(n)/p^3, p=Prime[n].
%C Numerators of Sum[ 1/k^n, {k,1,n-1} ] are listed in A120347(n) = {1, 9, 1393, 257875, 47463376609, 940908897061, ...}.
%F a(n) = Numerator[ Sum[ 1/k^Prime[n], {k,1,Prime[n]-1} ]]. a(n) = Numerator[ Zeta[p] - Zeta[p,p] ], for p = Prime[n].
%F a(n) = A120347[ Prime[n] ].
%t Table[Numerator[Sum[1/k^Prime[n],{k,1,Prime[n]-1}]],{n,1,8}]
%Y Cf. A119722.
%Y Cf. A120347.
%K frac,nonn
%O 1,2
%A _Alexander Adamchuk_, Aug 16 2006, Oct 31 2006
|
