A120341 Sequence of pairs numerator(s(n)), denominator(s(n)) where s(n) is the n-th partial sum of 1/A119753(n).

1, 3, 8, 15, 71, 105, 886, 1155, 12673, 15015, 255802, 285285, 18447227, 20255235, 1366902806, 1478632155, 109463953829, 116811940245, 15332301522476, 16236859694055, 6624458815881211, 6998086528137705, 2875388753804702068

Offset

1,2

Comments

There are only 66 terms of A119753 known and s(66) is 0.95578109643864566820083634846514203365246166270989 to 50 decimal places. What is sum(1/A119753(k),k=1..infinity)?

Links

Table of n, a(n) for n=1..23.

Formula

a(2n-1) = numerator(s(n)), a(2n)=denominator(s(n)), where s(n)=sum(1/A119753(k),k=1..n).

Example

a(5)=71, a(6)=105 since s(3)=1/3+1/5+1/7=71/105.

Crossrefs

Cf. A119751, A119753.

Sequence in context: A303259 A192167 A065500 * A325904 A362273 A094357

Adjacent sequences: A120338 A120339 A120340 * A120342 A120343 A120344

Keyword

nonn

Author

Walter Kehowski, Jun 23 2006

Extensions

This is not really a sequence. The standard OEIS convention would be to split this into two cross-referenced sequences with keyword "frac". - N. J. A. Sloane, Jul 22 2006

Status

approved