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 A120216 Start with 100013 and repeatedly reverse the digits and add 2 to get the next term. 6

%I

%S 100013,310003,300015,510005,500017,710007,700019,910009,900021,

%T 120011,110023,320013,310025,520015,510027,720017,710029,920019,

%U 910031,130021,120033,330023,320035,530025,520037,730027,720039,930029,920041,140031

%N Start with 100013 and repeatedly reverse the digits and add 2 to get the next term.

%C Let T(S,Q) be the sequence obtained by starting with S and repeatedly reversing the digits and adding Q to get the next term. This is T(100013,2). 100013 is the first S for which T(S,2) reaches a cycle of length 1890. The cycle is simply the first 1890 terms, which then repeat. A full period is given in the table.

%H Klaus Brockhaus, <a href="/A120216/b120216.txt">Table of n, a(n) for n = 1,...,1890</a>

%H N. J. A. Sloane, <a href="/A117831/a117831.txt">Sequences of RADD type</a>

%Y Cf. A117521, A118514, A120214, A120215, A120217, A120218.

%K nonn,base

%O 1,1

%A _Klaus Brockhaus_, Jun 11 2006

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