login
This site is supported by donations to The OEIS Foundation.
Logo

Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A119963 Triangle T(n,k), 0<=k<=n, read by rows,with T(2n,2k)=T(2n+1,2k)=T(2n+1,2k+1)=T(2n+2,2k+1)=binomial(n,k). 4
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 2, 2, 1, 1, 1, 1, 3, 2, 3, 1, 1, 1, 1, 3, 3, 3, 3, 1, 1, 1, 1, 4, 3, 6, 3, 4, 1, 1, 1, 1, 4, 4, 6, 6, 4, 4, 1, 1, 1, 1, 5, 4, 10, 6, 10, 4, 5, 1, 1 (list; table; graph; refs; listen; history; internal format)
OFFSET

0,13

COMMENTS

Contribution from John P. McSorley (mcsorley60(AT)hotmail.com), Aug 24 2010: (Start)

A combinatorial interpretation of this triangle is as follows:

Ignore the first column of 1's of the above triangle and the call the (n,k)

entry of the new triangle formed RE(n,k).

Hence row 8 of the `RE(n,k)' triangle is 1 4 3 6 3 4 1 1.

Now see sequence A180171 for the definition of a k-reverse of n.

Briefly, a k-reverse of n is a k-composition of n which is cyclically equivalent to its reverse.

Sequence A180171 is the `R(n,k)' triangle read by rows where R(n,k) is the total number of k-reverses of n.

Then RE(n,k) is the number of k-reverses of n upto cyclic equivalence.

In sequence A180171 we have R(8,3)=9 because there are 9 3-reverses of 8.

In cyclically equivalent classes: {116,611,161} {224,422,242}, and {233,323,332};

since there are 3 such classes we have RE(8,3)=3.

Similarly, in A180171, we have R(8,6)=21 because all 21 6-compositions of 8

are 6-reverses of 8, but they come in 4 cyclically equivalent classes

(with representatives 111113, 111122, 111212, and 112112) hence RE(8,6)=4.

There is another (equivalent) interpretation for RE(n,k) involving k-subsets of Z_n,

the integers modulo n, and the multiplier -1. See the McSorley/Schoen paper below for more details.

In this case it is convenient to count k-subsets upto dihedral equivalence, rather than cyclic equivalence.

The counts are the same. The row sums of the `RE(n,k)' triangle give sequence A052955.

(End)

REFERENCES

John P.McSorley: Counting k-compositions of n with palindromic and related structures. Preprint, 2010. [From John P. McSorley (mcsorley60(AT)hotmail.com), Aug 24 2010]

John P.McSorley and Alan H. Schoen: On k-Ovals and (n, k, lambda)-Cyclic Difference Sets, and Related Topics. Preprint, 2010. [From John P. McSorley (mcsorley60(AT)hotmail.com), Aug 24 2010]

EXAMPLE

Triangle begins:

1;

1, 1;

1, 1, 1;

1, 1, 1, 1;

1, 1, 2, 1, 1;

1, 1, 2, 2, 1, 1;

1, 1, 3, 2, 3, 1, 1;

1, 1, 3, 3, 3, 3, 1, 1;

1, 1, 4, 3, 6, 3, 4, 1, 1,;

CROSSREFS

Cf. A007318, A051159.

The row sums of the T(n,k) triangle give sequence A029744 whose terms are 1 more than the terms of sequence A052955 (row sums of RE(n,k) triangle). See sequence A029744 where there is a reference to necklaces relevant to the combinatorial interpretation and the McSorley and McSorley/Schoen papers given here. [From John P McSorley (mcsorley60(AT)hotmail.com), Aug 31 2010]

Sequence in context: A055801 A155050 A140356 * A057790 A052307 A067059

Adjacent sequences:  A119960 A119961 A119962 * A119964 A119965 A119966

KEYWORD

nonn,tabl

AUTHOR

Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Aug 02 2006

EXTENSIONS

Corrected by Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Aug 20 2010

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Transforms | Puzzles | Hot | Classics
Recent Additions | More pages | Superseeker | Maintained by The OEIS Foundation Inc.

Content is available under The OEIS End-User License Agreement .

Last modified February 17 19:13 EST 2012. Contains 206085 sequences.