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%I #12 Apr 12 2023 11:08:14
%S 0,0,0,2,5,7,13,23,149,277,331,9433
%N Least increasing sequence of primes equal to determinants of sequence A119838 starting (1,1,1) of continuous blocks of 4 numbers.
%C The associated sequence of elements of the determinants is A119838 = 1, 1, 1, 3, 8, 31, 87, 340, 959, 3751, 10581, 41396.
%F a(0) = a(1) = a(2) = 0 (or any arbitrary nonprime < 2); for n>2: a(n) = min{prime p = b(n)*b(n-3) - b(n-1)*b(n-2) where b(n) = A119838(n)}.
%F Prime p = determinant [b(n-3),b(n-2),b(n-1),b(n)] = b(n)*b(n-3) - b(n-1)*b(n-2) is a prime greater than any previous prime in this sequence, where b(n) = A119838(n).
%e a(6) = 13 because of the prime determinant formed from a(3,4,5,6) = (3,8,31,87).
%e Namely 13 = | 3 8|
%e |31 87|.
%Y Cf. A000040, A119838.
%K nonn,more,uned
%O 0,4
%A _Jonathan Vos Post_, May 25 2006
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