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A119562
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Let F(n) = 2^(2^n) + 1 = the n-th Fermat number, M(n) = 2^n - 1 = the n-th Mersenne number. Then a(n) = F(n) - M(n) + 1 = 2^(2^n) + 1 - (2^n - 1) + 1 = 2^(2^n) - 2^n + 3.
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0
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4, 5, 15, 251, 65523, 4294967267, 18446744073709551555, 340282366920938463463374607431768211331, 115792089237316195423570985008687907853269984665640564039457584007913129639683
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OFFSET
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0,1
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LINKS
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FORMULA
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EXAMPLE
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F(1) = 2^(2^1)+1 = 5
M(1) = 2^1-1 = 1
F(1) - M(2) + 1 = 5
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PROG
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(PARI) fm2(n) = for(x=0, n, y=2^(2^x)-2^x+3; print1(y", "))
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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