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%I #3 Mar 30 2012 18:50:54
%S 0,1,1,1,2,2,2,2,3,4,4,4,5,5,5,5,5,6,7,7,7,7,7,7,8,9,9,9,9,9,9,9,10,
%T 11,11,12,13,13,13,13,13,13,13,13,14,14,14,14,15,15,16,16,16,16,17,17,
%U 17,17,17,17,17,17,17,17,18,19,19,20,21,22,23,23,24,24,24,24,24,24,24,24
%N Partial sums of A118605.
%C a(n) = number of ones in A118605 in the first n+1 terms.
%K nonn
%O 0,5
%A _Reinhard Zumkeller_, May 09 2006
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