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A118601
Partial sums of A058129.
1
1, 3, 10, 45, 273, 2510, 34069, 1703066
OFFSET
1,2
FORMULA
a(n) = SUM[i=1..n] A058129(i). a(n) = SUM[i=1..n] (2*A058133(i) - A058132(i)).
KEYWORD
hard,nonn
AUTHOR
Jonathan Vos Post, May 08 2006
EXTENSIONS
One more term from Jonathan Vos Post, Jul 20 2009
Edited by N. J. A. Sloane, Jul 25 2009
STATUS
approved