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A118554 a(n) = 6*a(n-5)-a(n-10)+98 with a(0)=0, a(1)=11, a(2)=35, a(3)=56, a(4)=104, a(5)=147, a(6)=204, a(7)=336, a(8)=455, a(9)=731. 5
0, 11, 35, 56, 104, 147, 204, 336, 455, 731, 980, 1311, 2079, 2772, 4380, 5831, 7760, 12236, 16275, 25647, 34104, 45347, 71435, 94976, 149600, 198891, 264420, 416472, 553679, 872051, 1159340, 1541271, 2427495, 3227196, 5082804, 6757247, 8983304 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,2

COMMENTS

The sequence allows us to solve the equation X^2+(X+49)^2=Y^2.

Consider all Pythagorean triples (X,X+49,Z) ordered by increasing Z; sequence gives X values.

LINKS

Table of n, a(n) for n=0..36.

Index entries for linear recurrences with constant coefficients, signature (1, 0, 0, 0, 6, -6, 0, 0, 0, -1, 1).

FORMULA

a(0)=0, a(1)=11, a(2)=35, a(3)=56, a(4)=104, a(5)=147, a(6)=204, a(7)=336, a(8)=455, a(9)=731, a(10)=980, a(n)=a(n-1)+6*a(n-5)-6*a(n-6)- a(n-10)+a(n-11). [From Harvey P. Dale, Aug 19 2011]

G.f.: x*(11+24*x+21*x^2+48*x^3+43*x^4-9*x^5-12*x^6-7*x^7-12*x^8-9*x^9)/((1-x)*(1-6*x^5+x^10)). [Colin Barker, Apr 09 2012]

MATHEMATICA

LinearRecurrence[{1, 0, 0, 0, 6, -6, 0, 0, 0, -1, 1}, {0, 11, 35, 56, 104, 147, 204, 336, 455, 731, 980}, 40] (* Harvey P. Dale, Aug 19 2011 *)

CROSSREFS

Sequence in context: A114445 A054475 A029540 * A233546 A092069 A103115

Adjacent sequences:  A118551 A118552 A118553 * A118555 A118556 A118557

KEYWORD

nonn,easy

AUTHOR

Mohamed Bouhamida (bhmd95(AT)yahoo.fr), May 07 2006

STATUS

approved

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Last modified June 22 12:17 EDT 2017. Contains 288613 sequences.