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n-th central term of triangle A118032 divided by n+1 for n>=0, where the matrix square of A118032 forms a diagonal bisection of A118032.
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%I #3 Mar 30 2012 18:36:56

%S 1,1,2,6,10,34,52,229,324,973,1316,5988,7986,20208,26256,112669,

%T 144242,348661,436424,2101172,2662972,5911779,7366040,27473425,

%U 34012310,72163847,88028512,413490686,510895170,1067092215,1303755984,4229661687

%N n-th central term of triangle A118032 divided by n+1 for n>=0, where the matrix square of A118032 forms a diagonal bisection of A118032.

%F a(n) = A118038(n)/(n+1) for n>=0.

%Y Cf. A118032 (triangle), A118038 (central terms); related triangles: A118040 (A118032^2), A118045.

%K nonn

%O 0,3

%A _Paul D. Hanna_, Apr 10 2006