%I #7 Mar 30 2012 18:37:44
%S 0,1,-1,-2,0,-1,1,0,1,-1,1,2,0,-3,2,2,0,-1,0,1,0,-1,1,0,0,-1,1,3,0,-1,
%T -1,-2,0,0,0,2,0,-2,2,2,0,2,-1,0,-2,-2,1,-2,-1,0,1,3,0,-1,-1,1,1,0,1,
%U -1,0,-1,0,1,0,2,-1,0,0,3,-1,-2,0,-2,0,3,-2,1,-1,-4,-1,-1,1,-3,0,1,2,2,0,2,-1,3,2,-1,1,4,0,1,-1,1,0,-1
%N Column 2 of triangle A117162; equals the Moebius transform of A008683 (column 1 of A117162) preceded by a zero.
%C The inverse Moebius transform of A117164 (column 3 of A117162) equals this sequence preceded by a zero.
%F Equals the Moebius transform of column 1 preceded by a zero:
%F [0,1,-1,-2,0,-1,1,0,...] = Moebius([0, 1,-1,-1,0,-1,1,-1,...]).
%Y Cf. A117162, A112682, A008683 (column 1); A117164 (column 3).
%K sign
%O 1,4
%A _Wouter Meeussen_ and _Paul D. Hanna_, Mar 05 2006