OFFSET
1,8
COMMENTS
FORMULA
Column k+1 equals the Moebius transform of column k preceded by a zero, where column k includes the k-1 zeros above the diagonal, for k>=1, starting with A008683 in column 1.
EXAMPLE
Column 1 equals A008683 = Moebius transform of [1,0,0,0,...].
Column 2 = Moebius transform of column 1 preceded by a zero: [0,1,-1,-2,0,-1,1,0,...] = Moebius([0, 1,-1,-1,0,-1,1,-1,...]).
Column 3 = Moebius transform of column 2 preceded by a zero: [0,0,1,-1,-2,-1,-1,2,...] = Moebius([0, 0,1,-1,-2,0,-1,1,...]).
Column 4 = Moebius transform of column 3 preceded by a zero: [0,0,0,1,-1,-2,-1,-2,...] = Moebius([0, 0,0,1,-1,-2,-1,-1,...]).
Triangle begins:
1;
-1, 1;
-1,-1, 1;
0,-2,-1, 1;
-1, 0,-2,-1, 1;
1,-1,-1,-2,-1, 1;
-1, 1,-1,-1,-2,-1, 1;
0, 0, 2,-2,-1,-2,-1, 1;
0, 1,-1, 2,-2,-1,-2,-1, 1;
1,-1, 3, 0, 1,-2,-1,-2,-1, 1;
-1, 1,-1, 3, 0, 1,-2,-1,-2,-1, 1;
0, 2, 2, 0, 4,-1, 1,-2,-1,-2,-1, 1;
-1, 0, 2, 2, 0, 4,-1, 1,-2,-1,-2,-1, 1; ...
CROSSREFS
KEYWORD
sign,tabl
AUTHOR
Wouter Meeussen and Paul D. Hanna, Mar 05 2006
STATUS
approved