OFFSET
1,1
COMMENTS
This is to Lucas numbers as A117067 "Decimal value of binary number whose n-th 1 is followed by F(n) 0's" is to Fibonacci numbers. Primes include a(2) = 37 and a(3) = 593.
FORMULA
a(0) = 1, for positive n: a(n+1) = 1 + a(n)*2^(1+L(n)) = 1 + a(n)*2^(1+A000032(n)).
EXAMPLE
a(1) = 9 because 1001 (base 2) = 1 + 2^(1+2) = 9 (base 10), where the two 0's correspond to L(0) = A000032(0) = 2.
a(2) = 37 because 100101 (base 2) = 1 + (1 + 2^(1+2))*2^(1+1) = 37 (base 10).
a(3) = 593 because 1001010001 (base 2) = 1 + (1 + (1 + 2^(1+2))*2^(1+1))*2^(1+3) = 593(base 10).
MATHEMATICA
a[0] = 1; a[n_] := a[n] = 1 + a[n-1]*2^(1 + LucasL[n-1]); a /@ Range[10] (* Giovanni Resta, Jun 15 2016 *)
CROSSREFS
KEYWORD
base,easy,nonn
AUTHOR
Jonathan Vos Post, Apr 17 2006
STATUS
approved