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A116857
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Triangle read by rows: T(n,k) is the number of partitions of n into distinct odd parts, the largest of which is k (n>=1, k>=1).
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1
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1, 0, 0, 0, 1, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 2, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 2, 0, 1, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 2, 0, 1, 0, 1, 0, 1, 0, 1
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,137
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COMMENTS
| Both rows 2n-1 and 2n have 2n-1 terms each. Row sums yield A000700. T(n,2k)=0 Sum(k*T(n,k),k>=1)=A092316(n).
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FORMULA
| G.f.=sum(t^(2j-1)*x^(2j-1)*product(1+x^(2i-1), i=1..j-1), j=1..infinity).
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EXAMPLE
| T(20,11)=2 because we have [11,9] and [11,5,3,1].
T(30,17)=3 because we have [17,13],[17,9,3,1] and [17,7,5,1].
Triangle starts:
1;
0;
0,0,1;
0,0,1;
0,0,0,0,1;
0,0,0,0,1;
0,0,0,0,0,0,1;
0,0,0,0,1,0,1;
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MAPLE
| g:=sum(t^(2*j-1)*x^(2*j-1)*product(1+x^(2*i-1), i=1..j-1), j=1..30): gser:=simplify(series(g, x=0, 22)): for n from 1 to 20 do P[n]:=sort(coeff(gser, x^n)) od: for n from 1 to 20 do seq(coeff(P[n], t^j), j=1..2*ceil(n/2)-1) od; # yields sequence in triangular form
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CROSSREFS
| Cf. A092316.
Sequence in context: A105348 A016406 A129182 * A158971 A121467 A071325
Adjacent sequences: A116854 A116855 A116856 * A116858 A116859 A116860
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KEYWORD
| nonn,tabf
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AUTHOR
| Emeric Deutsch (deutsch(AT)duke.poly.edu), Feb 24 2006
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