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 A116679 Triangle read by rows: T(n,k) is the number of partitions of n into distinct part and having exactly k even parts (n >= 0, k >= 0). 2
 1, 1, 0, 1, 1, 1, 1, 1, 1, 2, 1, 2, 1, 1, 3, 1, 2, 3, 1, 2, 4, 2, 2, 5, 3, 2, 6, 4, 3, 7, 4, 1, 3, 8, 6, 1, 3, 10, 8, 1, 4, 11, 10, 2, 5, 13, 11, 3, 5, 15, 14, 4, 5, 18, 18, 5, 6, 20, 21, 7, 7, 23, 24, 9, 1, 8, 26, 29, 12, 1, 8, 30, 36, 14, 1, 9, 34, 41, 18, 2, 11, 38, 47, 23, 3, 12, 43, 55, 28, 4 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,10 COMMENTS Row n contains floor((1 + sqrt(1+4*n))/2) terms. Row sums yield A000009. T(n,0) = A000700(n), T(n,1) = A096911(n) for n >= 1. Sum_{k>=0} k*T(n,k) = A116680(n). LINKS G. C. Greubel, Rows n = 0..100 of triangle, flattened FORMULA G.f.: Product_{j>=1} (1+x^(2*j-1))*(1+t*x^(2*j)). EXAMPLE T(9,2)=2 because we have [6,2,1] and [4,3,2]. Triangle starts:   1;   1;   0, 1;   1, 1;   1, 1;   1, 2;   1, 2, 1;   1, 3, 1; MAPLE g:=product((1+x^(2*j-1))*(1+t*x^(2*j)), j=1..25): gser:=simplify(series(g, x=0, 38)): P[0]:=1: for n from 1 to 27 do P[n]:=sort(coeff(gser, x^n)) od: for n from 0 to 27 do seq(coeff(P[n], t, j), j=0..floor((sqrt(1+4*n)-1)/2)) od; # yields sequence in triangular form MATHEMATICA With[{m=25}, CoefficientList[CoefficientList[Series[Product[(1+x^(2*j- 1))*(1+t*x^(2*j)), {j, 1, m+2}], {x, 0, m}, {t, 0, m}], x], t]]//Flatten (* G. C. Greubel, Jun 07 2019 *) CROSSREFS Cf. A000009, A000700, A096911, A116680. Sequence in context: A008289 A326625 A188884 * A146290 A323345 A135539 Adjacent sequences:  A116676 A116677 A116678 * A116680 A116681 A116682 KEYWORD nonn,tabf AUTHOR Emeric Deutsch, Feb 22 2006 STATUS approved

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Last modified October 18 02:23 EDT 2019. Contains 328135 sequences. (Running on oeis4.)