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a(2*n+1) = 5*a(n), a(2*n+2) = 6*a(n) + a(n-1).
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%I #14 Dec 17 2022 06:56:57

%S 1,5,6,25,31,30,41,125,156,155,211,150,211,205,276,625,791,780,1061,

%T 775,1086,1055,1421,750,1111,1055,1416,1025,1441,1380,1861,3125,4026,

%U 3955,5371,3900,5471,5305,7146,3875,5711,5430,7291,5275,7416,7105,9581,3750

%N a(2*n+1) = 5*a(n), a(2*n+2) = 6*a(n) + a(n-1).

%H G. C. Greubel, <a href="/A116553/b116553.txt">Table of n, a(n) for n = 0..2500</a>

%F From _G. C. Greubel_, Oct 2016: (Start)

%F a(2*n+1) = 5*a(n).

%F a(2*n+2) = 6*a(n) + a(n-1). (End)

%t b[0] := 0; b[1] := 1;

%t b[n_?EvenQ] := b[n] = 5*b[n/2];

%t b[n_?OddQ] := b[n] = 6*b[(n - 1)/2] + b[(n - 3)/2];

%t Table[b[n], {n, 1, 70}]

%Y Cf. A116528, A116529, A116552, A116554, A116555.

%K nonn,easy

%O 0,2

%A _Roger L. Bagula_, Mar 15 2006

%E New name using formula, _Joerg Arndt_, Dec 17 2022