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Numbers that can be expressed as the ratio of the product and the sum of consecutive prime numbers starting from 2.
18

%I #45 Sep 08 2022 08:45:24

%S 1,3,125970,1278362451795,305565807424800745258151050335,

%T 2099072522743338791053378243660769678400212601239922213271230,

%U 330455532167461882998265688366895823334392289157931734871641555

%N Numbers that can be expressed as the ratio of the product and the sum of consecutive prime numbers starting from 2.

%C Let prime(i) denote the i-th prime (A000040). Let F(m) = (Product_{i=1..m} prime(i)) / (Sum_{i=1..m} prime(i)). Sequence gives integer values of F(m) and A051838 gives corresponding values of m. - _N. J. A. Sloane_, Oct 01 2011

%D G. Balzarotti and P. P. Lava, Le sequenze di numeri interi, Hoepli, 2008, p. 158.

%H Amiram Eldar, <a href="/A116536/b116536.txt">Table of n, a(n) for n = 1..81</a> (terms 1..42 from Vincenzo Librandi)

%F a(n) = A002110(A051838(n)) / A007504(A051838(n)). - _Reinhard Zumkeller_, Oct 03 2011

%F a(n) = A159578(n)/A001414(A159578(n)). - _Amiram Eldar_, Nov 02 2020

%e a(1) = 1 because 2/2 = 1.

%e a(2) = 3 because (2*3*5)/(2+3+5) = 30/10 = 3.

%e a(3) = 125970 because (2*3*5*7*11*13*17*19)/(2+3+5+7+11+13+17+19) = 9699690/77 = 125790.

%p P:=proc(n) local i,j, pp,sp; pp:=1; sp:=0; for i from 1 by 1 to n do pp:=pp*ithprime(i); sp:=sp+ithprime(i); j:=pp/sp; if j=trunc(j) then print(j); fi; od; end: P(100);

%t seq = {}; sum = 0; prod = 1; p = 1; Do[p = NextPrime[p]; prod *= p; sum += p; If[Divisible[prod, sum], AppendTo[seq, prod/sum]], {50}]; seq (* _Amiram Eldar_, Nov 02 2020 *)

%o (Magma) [p/s: n in [1..40] | IsDivisibleBy(p,s) where p is &*[NthPrime(i): i in [1..n]] where s is &+[NthPrime(i): i in [1..n]]]; // _Bruno Berselli_, Sep 30 2011

%o (Haskell)

%o import Data.Maybe (catMaybes)

%o a116536 n = a116536_list !! (n-1)

%o a116536_list = catMaybes $ zipWith div' a002110_list a007504_list where

%o div' x y | m == 0 = Just x'

%o | otherwise = Nothing where (x',m) = divMod x y

%o -- _Reinhard Zumkeller_, Oct 03 2011

%Y Cf. A001414, A108552, A067111, A051838, A140763, A141092, A159578.

%Y Subsequence of A325307.

%K nonn,easy

%O 1,2

%A _Paolo P. Lava_ & _Giorgio Balzarotti_, Mar 27 2006