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A116482 Triangle read by rows: T(n,k) is the number of partitions of n having k even parts (n>=0, 0<=k<=floor(n/2)). 3
1, 1, 1, 1, 2, 1, 2, 2, 1, 3, 3, 1, 4, 4, 2, 1, 5, 6, 3, 1, 6, 8, 5, 2, 1, 8, 11, 7, 3, 1, 10, 14, 10, 5, 2, 1, 12, 19, 14, 7, 3, 1, 15, 24, 19, 11, 5, 2, 1, 18, 31, 26, 15, 7, 3, 1, 22, 39, 34, 21, 11, 5, 2, 1, 27, 49, 45, 29, 15, 7, 3, 1, 32, 61, 58, 39, 22, 11, 5, 2, 1, 38, 76, 75, 52, 30 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,5

COMMENTS

Row n has 1 + floor(n/2) terms. Row sums are the partition numbers (A000041).

Column 0 yields A000009. Column 1 yields A038348. Column 2 yields A096778.

Sum_{k=0..floor(n/2)}k*T(n,k) = A066898(n).

From Gregory L. Simay, Nov 02 2015: (Start)

If n<=2k+1, T(n+2k,k) = A000041(n), the number of partitions of n.

T(n+2k,k) = the convolution of A000009(n-2j),which are the strict partitions of (n-2j), and p(j+k,k), which are the number of partitions of j+k having exactly k parts.

T(n+2k,k) = e(n,k) where e(n,0)= A000009(n) and e(n,k) = e(n,k-1) + e(n-2k,k-1) + e(n-4k,k-1) + ... .(End)

LINKS

Alois P. Heinz, Rows n = 0..200, flattened

FORMULA

G.f.: G(t,x) = 1/Product_{j>=1}((1-x^(2j-1))(1-tx^(2j))).

From Gregory L. Simay, Nov 03 2015: (Start)

G.f.: T(n+2k,k) = g.f.: e(n,k) = Product_{j>=1}(1-x^2*(k+j))*p(x), where p(x) is the g.f. of the partitions of x. If n<=2k+1, then the g.f. reduces to p(x).

T(n+2k,k) = T(n+2k-2,k-1) + T(n,k).

(End)

EXAMPLE

T(7,2) = 3 because we have [4,2,1], [3,2,2] and [2,2,1,1,1].

Triangle starts:

   1;

   1;

   1,  1;

   2,  1;

   2,  2,  1;

   3,  3,  1;

   4,  4,  2,  1;

   5,  6,  3,  1;

   6,  8,  5,  2,  1;

   8, 11,  7,  3,  1;

  10, 14, 10,  5,  2, 1;

  12, 19, 14,  7,  3, 1;

  15, 24, 19, 11,  5, 2, 1;

  18, 31, 26, 15,  7, 3, 1;

  22, 39, 34, 21, 11, 5, 2, 1;

  27, 49, 45, 29, 15, 7, 3, 1;

Added entries for n=8 through n=15. - Gregory L. Simay, Nov 03 2015

From Gregory L. Simay, Nov 03 2015: (Start)

T(15,4) = T(7+2*4,4) = p(7) = 15, since 7 < 2*4 + 1.

T(15,3) = T(13,2) + T(9,3) = 26 + 3 = 29.

T(10,1) = T(8+2*1,1) = T(8,0) + T(6,0) + T(4,0) + T(2,0) + T(0,0) = 6 + 4 + 2 + 1 + 1 = 14.

T(15,3) = T(9+2*3) = e(9,3) = e(9,2) + e(3,2) = (e(9,1) + e(5,1) + e(1,1)) + e(3,1) = q(9) + q(7) + q(5) + q(3) + q(1) + q(5) + q(3) + q(1) + q(1) + q(3) + q(1) = q(9) + q(7) + 2*q(5) + 3*q(3) + 4*q(1) = 8 + 5 + 2*3 + 3*2 + 4*1 = 29 = the convolution sum of q(9-2j) with p(3+j,3).

(End)

MAPLE

g:=1/product((1-x^(2*j-1))*(1-t*x^(2*j)), j=1..20): gser:=simplify(series(g, x=0, 22)): P[0]:=1: for n from 1 to 18 do P[n]:=coeff(gser, x^n) od: for n from 0 to 18 do seq(coeff(P[n], t, j), j=0..floor(n/2)) od; # yields sequence in triangular form

# second Maple program:

b:= proc(n, i) option remember; local j; if n=0 then 1 elif i<1

      then 0 else []; for j from 0 to n/i do zip((x, y)->x+y, %,

      [`if`(irem(i, 2)=0, 0$j, [][]), b(n-i*j, i-1)], 0) od; %[] fi

    end:

T:= n-> b(n, n):

seq (T(n), n=0..30);  # Alois P. Heinz, Jan 07 2013

MATHEMATICA

nn=8; CoefficientList[Series[Product[1/(1-x^(2i-1))/(1-y x^(2i)), {i, 1, nn}], {x, 0, nn}], {x, y}]//Grid  (* Geoffrey Critzer, Jan 07 2013 *)

CROSSREFS

Cf. A000041, A038348, A066898, A103919.

Sequence in context: A109699 A029283 A264404 * A173306 A276430 A182594

Adjacent sequences:  A116479 A116480 A116481 * A116483 A116484 A116485

KEYWORD

nonn,tabf

AUTHOR

Emeric Deutsch, Feb 17 2006

STATUS

approved

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Last modified May 23 01:01 EDT 2017. Contains 286908 sequences.