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Number of partitions of n into parts with digital root = 5.
10

%I #4 Mar 30 2012 18:50:54

%S 0,0,0,0,1,0,0,0,0,1,0,0,0,1,1,0,0,0,1,1,0,0,1,1,1,0,0,2,1,1,0,1,2,1,

%T 1,0,2,2,1,1,1,3,2,1,1,3,3,2,1,2,4,3,2,1,4,5,3,2,2,6,5,3,2,5,7,5,3,3,

%U 8,8,5,3,6,10,8,5,4,10,11,8,5,8,13,12,8,6,13,15,12,8,10,18,16,12,9,17,21,17

%N Number of partitions of n into parts with digital root = 5.

%C a(n) = A114102(n) - A116371(n) - A116372(n) - A116373(n) - A116374(n) - A116376(n) - A116377(n) - A116378(n) - A114099(n).

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/DigitalRoot.html">Digital Root</a>

%e a(42) = #{32+5+5, 23+14+5, 14+14+14} = 3.

%Y Cf. A010888.

%Y A147706. [From _Reinhard Zumkeller_, Nov 11 2008]

%K nonn,base

%O 1,28

%A _Reinhard Zumkeller_, Feb 12 2006