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Number of partitions of n into parts with digital root = 3.
11

%I #4 Mar 30 2012 18:50:54

%S 0,0,1,0,0,1,0,0,1,0,0,2,0,0,2,0,0,2,0,0,3,0,0,4,0,0,4,0,0,5,0,0,6,0,

%T 0,7,0,0,8,0,0,10,0,0,11,0,0,13,0,0,15,0,0,17,0,0,19,0,0,23,0,0,26,0,

%U 0,29,0,0,33,0,0,38,0,0,42,0,0,48,0,0,54,0,0,61,0,0,68,0,0,77,0,0,85,0,0,96

%N Number of partitions of n into parts with digital root = 3.

%C a(n) = A114102(n) - A116371(n) - A116372(n) - A116374(n) - A116375(n) - A116376(n) - A116377(n) - A116378(n) - A114099(n).

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/DigitalRoot.html">Digital Root</a>

%F a(n) = A035382(floor(n/3))*0^(n mod 3).

%e a(21) = #{21, 12+3+3+3, 3+3+3+3+3+3+3} = 3.

%Y Cf. A010888.

%Y A147706. [From _Reinhard Zumkeller_, Nov 11 2008]

%K nonn,base

%O 1,12

%A _Reinhard Zumkeller_, Feb 12 2006