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Number of partitions of n into parts with digital root = 2.
10

%I #4 Mar 30 2012 18:50:54

%S 0,1,0,1,0,1,0,1,0,1,1,1,1,1,1,1,1,1,1,2,1,3,1,3,1,3,1,3,2,3,3,3,4,3,

%T 4,3,4,4,4,6,4,7,4,8,4,8,5,8,7,8,9,8,10,8,11,9,11,12,11,15,11,17,11,

%U 18,12,19,15,19,19,19,22,19,24,20,25,24,26,29,26,34,26,37,27,39,31,40,38,41

%N Number of partitions of n into parts with digital root = 2.

%C a(n) = A114102(n) - A116371(n) - A116373(n) - A116374(n) - A116375(n) - A116376(n) - A116377(n) - A116378(n) - A114099(n).

%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/DigitalRoot.html">Digital Root</a>

%e a(31) = #{29+2, 20+11, 11+2+2+2+2+2} = 3.

%Y Cf. A010888.

%Y A147706. [From _Reinhard Zumkeller_, Nov 11 2008]

%K nonn,base

%O 1,20

%A _Reinhard Zumkeller_, Feb 12 2006