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A116089
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Riordan array (1, x*(1+x)^3).
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3
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1, 0, 1, 0, 3, 1, 0, 3, 6, 1, 0, 1, 15, 9, 1, 0, 0, 20, 36, 12, 1, 0, 0, 15, 84, 66, 15, 1, 0, 0, 6, 126, 220, 105, 18, 1, 0, 0, 1, 126, 495, 455, 153, 21, 1, 0, 0, 0, 84, 792, 1365, 816, 210, 24, 1, 0, 0, 0, 36, 924, 3003, 3060, 1330, 276, 27, 1
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OFFSET
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0,5
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LINKS
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FORMULA
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G.f.: 1/(1-x*y*(1+x)^3).
Number triangle T(n,k) = C(3*k,n-k) = C(n,k)*C(4*k,n)/C(4*k,k).
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EXAMPLE
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Triangle begins as:
1;
0, 1;
0, 3, 1;
0, 3, 6, 1;
0, 1, 15, 9, 1;
0, 0, 20, 36, 12, 1;
0, 0, 15, 84, 66, 15, 1;
0, 0, 6, 126, 220, 105, 18, 1;
0, 0, 1, 126, 495, 455, 153, 21, 1;
0, 0, 0, 84, 792, 1365, 816, 210, 24, 1;
0, 0, 0, 36, 924, 3003, 3060, 1330, 276, 27, 1;
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MATHEMATICA
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Flatten[Table[Binomial[3k, n-k], {n, 0, 20}, {k, 0, n}]] (* Harvey P. Dale, Feb 05 2012 *)
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PROG
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(PARI) {T(n, k) = binomial(3*k, n-k)}; \\ G. C. Greubel, May 09 2019
(Magma) [[Binomial(3*k, n-k): k in [0..n]]: n in [0..12]]; // G. C. Greubel, May 09 2019
(Sage) [[binomial(3*k, n-k) for k in (0..n)] for n in (0..12)] # G. C. Greubel, May 09 2019
(GAP) Flat(List([0..12], n-> List([0..n], k-> Binomial(3*k, n-k) ))); # G. C. Greubel, May 09 2019
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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