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%I #3 Mar 30 2012 18:36:55
%S 1,2,18,200,2870,49392,976668,21697104,532727910,14275220960,
%T 413469332276,12845983030608,425442421627132,14941814934855200,
%U 554044899080129400,21608731448473756320,883563752144886420870
%N Central terms of triangle A116071, which equals Pascal's triangle to the matrix power of Pascal's triangle.
%F a(n) = (n+1)*A000108(n)*A000248(n).
%o (PARI) {a(n)=local(X=x+x*O(x^(2*n)),Y=y+y*O(y^n)); (2*n)!*polcoeff(polcoeff(exp(X*(Y+exp(X))),2*n,x),n,y)}
%Y Cf. A000248, A080108, A116071.
%K nonn
%O 0,2
%A _Paul D. Hanna_, Feb 03 2006
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