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%I #10 Jul 16 2021 01:35:38
%S 2326,3909,5196,5402,7061,7616,8402,8496,8499,9048,13565,15194,15298,
%T 15841,19304,19429,20516,21669,23260,23572,23875,23936,24299,24772,
%U 24952,25182,25281,26139,26499,26602,26818,26832,27287,27433,27757
%N Numbers k such that k^3 contains a pandigital substring.
%e 19429^3 = 73(3417629058)9.
%o (Python)
%o def haspan(s): return any(len(set(s[i:i+10]))==10 for i in range(len(s)-9))
%o print([m for m in range(30000) if haspan(str(m**3))]) # _Michael S. Branicky_, Feb 28 2021
%Y Cf. A115934, A115935, A115936, A115937, A115938.
%K nonn,base
%O 1,1
%A _Giovanni Resta_, Feb 06 2006
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