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A115424
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Integers n > 0 such that n XOR 62*n = 63*n.
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6
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1, 2, 4, 8, 16, 32, 64, 65, 128, 129, 130, 256, 257, 258, 260, 512, 513, 514, 516, 520, 1024, 1025, 1026, 1028, 1032, 1040, 2048, 2049, 2050, 2052, 2056, 2064, 2080, 4096, 4097, 4098, 4100, 4104, 4112, 4128, 4160, 4161, 8192, 8193, 8194, 8196, 8200, 8208
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OFFSET
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1,2
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LINKS
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FORMULA
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This sequence also seems to satisfy:
3*a(n) XOR 41*a(n) = 42*a(n);
5*a(n) XOR 35*a(n) = 38*a(n);
6*a(n) XOR 35*a(n) = 37*a(n);
7*a(n) XOR 35*a(n) = 36*a(n); etc.
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MATHEMATICA
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Select[Range[8300], BitXor[#, 62 #]==63 #&] (* Harvey P. Dale, Oct 31 2021 *)
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PROG
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(Perl)
$cnt=0;
foreach(1..8_000){
print ++$cnt, " $_\n" if ((62*$_)^$_)==63*$_;
}
(PARI) isok(n) = bitxor(n, 62*n) == 63*n; \\ Michel Marcus, Nov 11 2016
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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