|
|
A115022
|
|
a(n) = F(n-th squarefree)/product{p=primes,p|(n-th squarefree)} F(p), where F(m) is m-th Fibonacci number.
|
|
1
|
|
|
1, 1, 1, 1, 4, 1, 11, 1, 1, 29, 61, 1, 1, 421, 199, 1, 521, 1, 83204, 1, 19801, 3571, 141961, 1, 9349, 135721, 1, 10304396, 1, 64079, 1, 6376021, 1, 313671601, 43701901, 1149851, 1, 1, 3010349, 14736206161, 156055561996, 1, 2053059121
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,5
|
|
LINKS
|
|
|
EXAMPLE
|
The 7th squarefree integer is 10 = 2*5. So a(7) = F(10)/(F(2)F(5)) = 55/(1*5) = 11.
|
|
MAPLE
|
count:= 0:
for n from 1 while count < 50 do
if numtheory:-issqrfree(n) then
count:= count+1;
A[count]:= combinat:-fibonacci(n)/mul(combinat:-fibonacci(p), p=numtheory:-factorset(n))
fi
od:
|
|
MATHEMATICA
|
f[n_] := Fibonacci[n]/Times @@ (Fibonacci /@ FactorInteger[n][[;; , 1]]); f /@
Select[Range[70], SquareFreeQ[#] &] (* Amiram Eldar, Dec 04 2018 *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|