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A114899
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a(1)=0. a(n+1) = number of earlier terms a(k) (1 <=k <=n) where a(k)+n is a prime.
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3
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0, 0, 2, 3, 1, 3, 1, 2, 2, 3, 5, 5, 4, 3, 6, 4, 6, 7, 4, 5, 4, 3, 3, 4, 4, 8, 9, 9, 10, 6, 3, 6, 5, 8, 10, 9, 7, 14, 14, 13, 12, 10, 6, 11, 10, 7, 6, 11, 7, 11, 13, 9, 10, 12, 10, 14, 14, 19, 15, 13, 13, 16, 11, 15, 18, 16, 14, 18, 17, 20, 18, 12, 11, 16, 10, 13, 16, 13, 12, 18, 12, 10, 9, 18
(list; graph; refs; listen; history; internal format)
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OFFSET
| 1,3
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LINKS
| T. D. Noe, Table of n, a(n) for n=1..2000
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EXAMPLE
| If we add 10 to each of the first 10 terms of the sequence, we get
[10,10,12,13,11,13,11,12,12,13]. Of these only the two 11's and the three 13's are primes. So a(11) = 5.
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PROG
| (PARI) seq=vector(200); print1(0, ", "); for(j=1, 190, count=0; for(k=0, j-1, if(isprime(j+seq[k+1])==1, count=count+1; )); seq[j+1]=count; print1(seq[j+1], ", ")) - Matthew Conroy Feb 09 2006
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CROSSREFS
| Cf. A114897, A114898.
Cf. A123541
Sequence in context: A064442 A134411 A126044 * A023678 A128222 A057039
Adjacent sequences: A114896 A114897 A114898 * A114900 A114901 A114902
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KEYWORD
| nonn
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AUTHOR
| Leroy Quet Jan 05 2006
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EXTENSIONS
| More terms from Matthew Conroy Feb 09 2006
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