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A114780
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Least multiple of 2n-1 ending in prime(n). If prime(n) has k digits then a(n) == prime(n) (mod 10^k),0 if no such number exists. a(10r+5) =0.
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2
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2, 3, 5, 7, 711, 913, 117, 0, 323, 1729, 231, 437, 0, 243, 1247, 1953, 759, 0, 3367, 3471, 2173, 2279, 0, 4089, 2597, 28101, 45103, 0, 2109, 18113, 43127, 40131, 0, 1139, 22149, 34151, 37157, 0, 13167, 62173, 37179, 17181, 0, 38193, 33197, 17199, 86211
(list; graph; refs; listen; history; internal format)
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