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a(n) = (floor(sqrt(2)*10^n))^2.
14

%I #10 Jul 05 2017 21:12:05

%S 1,196,19881,1999396,199996164,19999899241,1999998409369,

%T 199999982358225,19999999932878736,1999999998944727844,

%U 199999999979325598129,19999999999912458800169,1999999999999731161391129,199999999999973116139112900,19999999999999857198323561481

%N a(n) = (floor(sqrt(2)*10^n))^2.

%H G. C. Greubel, <a href="/A114761/b114761.txt">Table of n, a(n) for n = 0..495</a>

%e a(1) = floor[2^(1/2)*10]^2 = 14^2 = 196.

%t f[n_] := Floor[ Sqrt@2*10^n]^2; Table[ f[n], {n, 0, 12}] (* _Robert G. Wilson v_ *)

%o (PARI) for(n=0, 50, print1((floor(sqrt(2)*10^n))^2, ", ")) \\ _G. C. Greubel_, Jul 05 2017

%Y Cf. A114762.

%K base,nonn

%O 0,2

%A _Amarnath Murthy_, Nov 17 2005

%E More terms from _Robert G. Wilson v_, Jan 03 2006

%E More terms from _Joshua Zucker_, May 05 2006